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Home/ Questions/Q 8574159
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Editorial Team
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Editorial Team
Asked: June 11, 20262026-06-11T19:24:42+00:00 2026-06-11T19:24:42+00:00

Here’s a test run in Firebug. I’m trying to make a jQuery object dynamically,

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Here’s a test run in Firebug. I’m trying to make a jQuery object dynamically, and then finding parts of it using class or id selectors. Notice how the find() calls give empty results.

>>> var testhtml = '<div class="oggi">h</div>'
undefined
>>> $(testhtml)
[div.oggi]
>>> $(testhtml).find(".oggi")
[]
>>> var testhtml2 = '<div id="yggi">hjhj</div>'
undefined
>>> $(testhtml2)
[div#yggi]
>>> $(testhtml2).find("#yggi")
[]

Should I interpret this as you are unable to do some jQuery operations on html that isn’t connected to the main DOM tree in the browser? Is there some other trick that I might use to make this work?

I managed to get something that worked better by making a temporary div in the html, loading the data there and then doing find().

My actual task is loading a piece of html using ajax, and then copying different parts of it to different places in the web page.

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  1. Editorial Team
    Editorial Team
    2026-06-11T19:24:43+00:00Added an answer on June 11, 2026 at 7:24 pm

    .find() is used to find the children, use .filter() instead.

    var testhtml = '<div class="oggi">h</div>';
    
    // if you want to check it whether has a class, use    
    console.log($(testhtml).is(".oggi"));
    
    // or you could use filter to get the element you want.
    console.log($(testhtml).filter('.oggi'));
    
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