Question

Here’s a trivial batch:

 @echo off
 if not .%1==.-b goto else
 echo Running with -b flag ON 
 goto endif
 :else
 echo Running with NO flags
 :endif

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Now, trying to run this from a scheduled task on a Windows Server 2003…

If the task is ran like: “C:\Test\test.bat” then the log (Schedlgu.txt) says:

“Test Job.job” (test.bat)
Started 7/14/2010 10:27:19 AM
“Test Job.job” (test.bat)
Finished 7/14/2010 10:27:19 AM
Result: The task completed with an exit code of (0).

However, when running like: “C:\Test\test.bat -b” then:

“Test Job.job” (test.bat -b) 7/14/2010 10:28:02 AM ** ERROR **
Unable to start task.
The specific error is:
0x80070005: Access is denied.
Try using the Task page Browse button to locate the application.

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The task is running under the Admin account (of the domain). I have also granted full access to this user to the local cmd.exe

Any thoughts why the task fails when running a batch with one argument?

Thx

Answer 1

Run the task with parameters like this:

"C:\Test\test.bat" -b

Note the different quoting!

The fisrt string inside quotes is always considered the file name, hence the error message you see.