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Editorial Team
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Editorial Team
Asked: May 14, 20262026-05-14T07:37:14+00:00 2026-05-14T07:37:14+00:00

Here’s an excerpt from Sun’s Java tutorials : A switch works with the byte

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Here’s an excerpt from Sun’s Java tutorials:

A switch works with the byte, short, char, and int primitive data types. It also works with enumerated types (discussed in Classes and Inheritance) and a few special classes that “wrap” certain primitive types: Character, Byte, Short, and Integer (discussed in Simple Data Objects).

There must be a good reason why the long primitive data type is not allowed. Anyone know what it is?

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  1. Editorial Team
    Editorial Team
    2026-05-14T07:37:15+00:00Added an answer on May 14, 2026 at 7:37 am

    I think to some extent it was probably an arbitrary decision based on typical use of switch.

    A switch can essentially be implemented in two ways (or in principle, a combination): for a small number of cases, or ones whose values are widely dispersed, a switch essentially becomes the equivalent of a series of ifs on a temporary variable (the value being switched on must only be evaluated once). For a moderate number of cases that are more or less consecutive in value, a switch table is used (the TABLESWITCH instruction in Java), whereby the location to jump to is effectively looked up in a table.

    Either of these methods could in principle use a long value rather than an integer. But I think it was probably just a practical decision to balance up the complexity of the instruction set and compiler with actual need: the cases where you really need to switch over a long are rare enough that it’s acceptable to have to re-write as a series of IF statements, or work round in some other way (if the long values in question are close together, you can in your Java code switch over the int result of subtracting the lowest value).

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