Question

Here’s an excerpt of the code.

int main(int argc, char*argv[])
string s;

if (argc == 2)
    argv[1] == s;             //I tried this with and without brackets

else if (argc == 1){
    cout << "Enter a number." << endl;
    cin >> s;
    }
else
    {    
    cout << "Use only one argument" << endl;
    }

cout << s << endl;

However, if there’s an argument (first condition) then it’s ALWAYS 0. Anyone know why?

Answer 1

This line

argv[1] == s;

should be

s = argv[1];

Your current code compares argv[1] to an empty string using ==, and discards the result of comparison. It looks like you are after getting the first argument into the string s, so you need an assignment.