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Home/ Questions/Q 8605833
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Editorial Team
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Editorial Team
Asked: June 12, 20262026-06-12T02:56:08+00:00 2026-06-12T02:56:08+00:00

here’s my action. public virtual JsonResult AddSearch() { var data = new { Id

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here’s my action.

    public virtual JsonResult AddSearch()
    {
        var data = new { Id = food.Id, Image = food.Image, Name = food.Name};

        return Json(data, JsonRequestBehavior.AllowGet);
    }

here’s my aJax form

    @using (Ajax.BeginForm("AddSearch", "Home", new AjaxOptions { OnSuccess = "AddSearch" }))

my javascript file.

    function AddSearch() {
        alert("sdfsdfsdf");
    }

it works, I see the alert box. my question is how I can get the “Id”, “Name” and “Image” returned by JsonResult. I tried

        alert("sdfsdfsdf");

it’s not working.

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-12T02:56:10+00:00Added an answer on June 12, 2026 at 2:56 am

    MVC (to be precise unobtrusiveAjax helpers) will pass the standard jQuery.ajax success(data, textStatus, jqXHR)callback arguments to the OnSuccess method.

    So you just need to add the parameters to your AddSearch method:

    function AddSearch(data, status, xhr) {
            // you can access your properties from data
            alert(data.Name);
    }
    
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