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Home/ Questions/Q 813305
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Editorial Team
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Editorial Team
Asked: May 15, 20262026-05-15T01:20:14+00:00 2026-05-15T01:20:14+00:00

Here’s my class definition: class A { public: void do_lengthy_work() { cout << working.

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Here’s my class definition:

class A {
    public:
        void do_lengthy_work() {
        cout << "working." << endl;
        }
};

I have an object of type A, and I want to call do_lengthy_work() on it:

A a;
a.do_lengthy_work();

Is it also possible to call the same method using some variant of the following?

A::do_lengthy_work(a);
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  1. Editorial Team
    Editorial Team
    2026-05-15T01:20:14+00:00Added an answer on May 15, 2026 at 1:20 am

    You can wrap the function with mem_fun_ref:

    mem_fun_ref(&A::do_lengthy_work)(a);
    

    This can be very useful for STL algorithms like for_each:

    std::vector<A> vec;
    std::for_each(vec.begin(), vec.end(), mem_fun_ref(&A::do_lengthy_work));
    

    If you have an A *, you would use mem_fun:

    std::vector<A *> vecp;
    std:for_each(vecp.begin(), vecp.end(), mem_fun(&A::do_lengthy_work));
    
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