Question

Here’s my code:

 1. "special_filter,|filter_str,(&(a=1)(c=11)(p=c=11,o=m,d=4))"


 2.{ "a" =>"1", "c" => "11" , "p" => "c=11,o=m,d=4"}

Answer 1

#!/usr/bin/ruby

string = "special_filter,|filter_str,(&(a=1)(c=11)(p=c=11,o=m,d=4))"
hash = {}
string.slice(/\(&.*\)/).split(")").each do |match|
  match.tr("(&","").split("=",2).each_slice(2) { |key, value| hash[key] = value }
end

Line by line:

Line 1: Set a variable, string, with the starting string.

string = "special_filter,|filter_str,(&(a=1)(c=11)(p=c=11,o=m,d=4))"

Line 2: Set a variable, hash, with an empty hash to fill.

hash = {}

Line 3:

• Cut out the portion of the string that matches this regexp

string.slice(/\(&.*\)/) => "(&(a=1)(c=11)(p=c=11,o=m,d=4))"

The regexp is bookended with forward slashes (/regexp goes here/).
Parentheses have special meaning in regex, so they must be escaped with backslashes.
The & matches the & in the string.
In regex, a . means any character.
* means none to unlimited of the preceding character.
So this regex matches (&) as well as (&fjalsdkfj).

• Split the string by right parentheses

string.slice(/\(&.*\)/).split(")") => ["(&(a=1", "(c=11", "(p=c=11,o=m,d=4"]

• Then iterate through the array of results

string.slice(/\(&.*\)/).split(")").each do |match|

Line 4:

• Take the iteration and remove unwanted characters from it

match.tr("(&","")

• Split it one time, using the first = sign

match.tr("(&","").split("=",2)

• Use the 2 value array as a key and value on the hash

match.tr("(&","").split("=",2).each_slice(2) { |key, value| hash[key] = value }