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Home/ Questions/Q 8535779
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Editorial Team
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Editorial Team
Asked: June 11, 20262026-06-11T10:30:48+00:00 2026-06-11T10:30:48+00:00

Here’s my code… char* m1; char* m2 = sth; strcpy(m1, m2); That code threw

  • 0

Here’s my code…

char* m1;
char* m2 = "sth";
strcpy(m1, m2);

That code threw run-time errors, so I tried…

char m1[];
char m2[] = "sth"; 

That can run with no errors. However, I want to use…

char* s

What sould I do?

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  1. Editorial Team
    Editorial Team
    2026-06-11T10:30:50+00:00Added an answer on June 11, 2026 at 10:30 am

    Problem is you are not allocating any memory to store the result of the strcpy method. You need:

    char* m1 = (char *) malloc(sizeof(char) * 4) /* 4 being the size of 3 chars + trailing \0 */
    char* m2 = "sth";
    

    Than you can do the strcpy

    And in the end you have to free any dynamically allocated memory a.g.

    free(m1)
    

    m2 is allocated statically and doesn’t has to be freed.

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