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Home/ Questions/Q 6751837
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Editorial Team
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Editorial Team
Asked: May 26, 20262026-05-26T12:58:28+00:00 2026-05-26T12:58:28+00:00

Here’s my code: for (int arrayIndex = 0; arrayIndex < 5; arrayIndex++) { PhoneBookEntry

  • 0

Here’s my code:

for (int arrayIndex = 0; arrayIndex < 5; arrayIndex++)
    {

        PhoneBookEntry PhoneBook = new PhoneBookEntry();
        System.out.println("Please enter a name");
        tempName = keyboard.nextLine();
        PhoneBook.setName(tempName);
        System.out.println("Please enter a corresponding phone number");
        tempNum = keyboard.nextInt();
        PhoneBook.setPhoneNum(tempNum);

        EntryList.add(PhoneBook);

    }

Apparently there is a problem with the nextLine method on the second try. How could I fix this? I am not allowed to use any class other than scanner for this.

Thanks

EDIT: The error it gives is an exception:

Exception in thread "main" java.util.InputMismatchEx
        at java.util.Scanner.throwFor(Unknown Source
        at java.util.Scanner.next(Unknown Source)
        at java.util.Scanner.nextInt(Unknown Source)
        at java.util.Scanner.nextInt(Unknown Source)
        at PhoneBookApp.main(PhoneBookApp.java:39)
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  1. Editorial Team
    Editorial Team
    2026-05-26T12:58:29+00:00Added an answer on May 26, 2026 at 12:58 pm

    I think you should use a String type for the phone numbers rather than an int. It would give you mismatch exceptions with certain numbers. In this instance using a String would be more appropriate.

    System.out.println("Please enter a corresponding phone number");
    String tempNum = keyboard.nextLine();
    
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