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Home/ Questions/Q 6242811
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Editorial Team
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Editorial Team
Asked: May 24, 20262026-05-24T12:01:27+00:00 2026-05-24T12:01:27+00:00

Here’s my code: import java.util.Scanner; public class Arrays { public static void main(String[] args)

  • 0

Here’s my code:

import java.util.Scanner;

public class Arrays {
    public static void main(String[] args) {
        Arrays psvm = new Arrays();
        psvm.start();
    }

    public void start() {
        Scanner ben = new Scanner(System.in);
        int[] arr = new int[4];
        int[] arrs = new int[4];
        for (int i = 0; i < arr.length; i++) {
            arr[i] = ben.nextInt();
        }
        check(arr, arrs);
    }

    public void check(int arr[], int arrs[]) {
        for (int i = 0; i < arr.length; i++) {
            arrs[i] = arr[i];
        }
        for (int i : arrs) {
            System.out.println(arrs[i]);
        }
    }
}

The enhanced for loop gives ArrayIndexOutOfBoundsException:

for (int i : arrs) {
    System.out.println(arrs[i]);
}

While this for loop statement works. Why? What’s wrong with the code?

for (int i = 0; i < arrs.length; i++) {
    System.out.println(arrs[i]);
}
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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-24T12:01:29+00:00Added an answer on May 24, 2026 at 12:01 pm

    In this case, i will be assigned to each element in the array – it is not an index into the array.

    What you want to do is:

    for(int i : arrs)
    {
        System.out.println(i);
    }
    

    In your code, you’re trying to select the integer at the array index referenced by the iteration object. In other words, your code is equivalent to:

    for(int idx = 0; idx < arrs.length; idx++)
    {
        int i = arrs[idx];
        System.out.println(arrs[i]);
    }
    
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