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Home/ Questions/Q 774443
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Editorial Team
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Editorial Team
Asked: May 14, 20262026-05-14T19:07:59+00:00 2026-05-14T19:07:59+00:00

Here’s my code: import urllib2.request response = urllib2.urlopen(http://www.google.com) html = response.read() print(html) Any help?

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Here’s my code:

import urllib2.request

response = urllib2.urlopen("http://www.google.com")
html = response.read()
print(html)

Any help?

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  1. Editorial Team
    Editorial Team
    2026-05-14T19:07:59+00:00Added an answer on May 14, 2026 at 7:07 pm

    As stated in the urllib2 documentation:

    The urllib2 module has been split across several modules in Python 3 named urllib.request and urllib.error. The 2to3 tool will automatically adapt imports when converting your sources to Python 3.

    So you should instead be saying

    from urllib.request import urlopen
    html = urlopen("http://www.google.com/").read()
    print(html)
    

    Your current, now-edited code sample is incorrect because you are saying urllib.urlopen("http://www.google.com/") instead of just urlopen("http://www.google.com/").

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