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Home/ Questions/Q 4086800
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Editorial Team
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Editorial Team
Asked: May 20, 20262026-05-20T18:46:26+00:00 2026-05-20T18:46:26+00:00

heres my code so you see what i’m trying to do, which obviously isn’t

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heres my code so you see what i’m trying to do, which obviously isn’t working:

        $('#selector').change(function() {  
        if ($(this).val().length > 0)
        {           
            $.ajax({
                type: "POST",
                url: "ajax.php",
                data: "id="+$(this).val(),
                success: function(data){
                    if (data != 'error')
                    {
                        $('#main_url').val(data[2]);
                        $('#main_url_title').val(data[3]);
                    }
                }
            });
        }
    });

i set up an alert(data); and all it pops up with is “Array”. so now my 2 fields are being populated with “r” and “a”…what is the correct way of doing this?

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  1. Editorial Team
    Editorial Team
    2026-05-20T18:46:27+00:00Added an answer on May 20, 2026 at 6:46 pm

    I think you may encode php array in json data, and then use json with jquery

    Add in ajax.php something like echo json_encode($your_php_array)

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