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Editorial Team
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Asked: 2026-05-15T13:07:33+00:00

here’s my code that works thanks to Jim b: SELECT IIf([Lab Occurrence Form].[1 0

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here’s my code that works thanks to Jim b:

SELECT IIf([Lab Occurrence Form].[1 0 Preanalytical (Before Testing)] Like '*1.11 Other*','1.11 Other',[Lab Occurrence Form].[1 0 Preanalytical (Before Testing)]) AS [Occurrence Code], Count([Lab Occurrence Form].[1 0 Preanalytical (Before Testing)])
FROM [Lab Occurrence Form]
WHERE ((([Lab Occurrence Form].[Occurrence Date]) Between [Forms]![Meeting_Reasons_Frequency]![Text4] And [Forms]![Meeting_Reasons_Frequency]![Text2]))
GROUP BY [Lab Occurrence Form].[1 0 Preanalytical (Before Testing)]
HAVING ((Count([Lab Occurrence Form].[1 0 Preanalytical (Before Testing)]))<>0)
ORDER BY Count([Lab Occurrence Form].[1 0 Preanalytical (Before Testing)]) DESC;

it returns this:

1.1 Specimen Mislabeled 159
1.3 QNS-Quantity Not Sufficient 84
1.9 QNS- Specimen Spilled in transit    72
1.6 Test Requisition Missing    17
1.11 Other  3
1.11 Other  3
1.1 Specimen Mislabeled-new ID # given  2
1.11 Other  2
1.11 Other  2
1.1 Specimen Mislabeled & 1.6 Test Requisition Missing  1
1.11 Other  1
1.11 Other  1
1.11 Other  1
1.11 Other  1
1.11 Other  1
? Nothing in comments portion of QuikLab    1
1.11 Other  1
1.11 Other  1
1.4 Tests Missed/ Wrong Test Ordered    1
1.4 Tests Missed/Wrong Test Ordered 1
1.6 Test Requisition Missing & 1.7 Specimen Lost    1
1.8 Specimen not handled/processed correctly & 1.10 Operator Error(?)   1
1.11 Other  1
1.11 Other  1

this is exactly what i need HOWEVER, there is one slight thing off. i need it to be counting ‘1.11 Other’

how do i do it? another words this is the output I need:

? Nothing in comments portion of QuikLab    1
1.1 Specimen Mislabeled 159
1.1 Specimen Mislabeled & 1.6 Test Requisition Missing  1
1.1 Specimen Mislabeled-new ID # given  2
1.11 Other  19
1.3 QNS-Quantity Not Sufficient 84
1.4 Tests Missed/ Wrong Test Ordered    1
1.4 Tests Missed/Wrong Test Ordered 1
1.6 Test Requisition Missing    17
1.6 Test Requisition Missing & 1.7 Specimen Lost    1
1.8 Specimen not handled/processed correctly & 1.10 Operator Error(?)   1
1.9 QNS- Specimen Spilled in transit    72

as you can see there is only one occurrence of 1.11 Other and a total count of 19

JIM B suggests this:

Use your IIF statement all the way through your group by and having clauses – Jim B

but i do not understand how to implement it. please help!

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1 Answer

  1. Editorial Team

    More of a sql server guy so i am not sure if you can do this but have you tried:

    SELECT IIf([Lab Occurrence Form].[1 0 Preanalytical (Before Testing)] Like '*1.11 Other*','1.11 Other',[Lab Occurrence Form].[1 0 Preanalytical (Before Testing)]) AS [Occurrence Code], Count([Lab Occurrence Form].[1 0 Preanalytical (Before Testing)])
FROM [Lab Occurrence Form]
WHERE ((([Lab Occurrence Form].[Occurrence Date]) Between [Forms]![Meeting_Reasons_Frequency]![Text4] And [Forms]![Meeting_Reasons_Frequency]![Text2]))
GROUP BY IIf([Lab Occurrence Form].[1 0 Preanalytical (Before Testing)] Like '*1.11 Other*','1.11 Other',[Lab Occurrence Form].[1 0 Preanalytical (Before Testing)])
HAVING ((Count([Lab Occurrence Form].[1 0 Preanalytical (Before Testing)]))<>0)
ORDER BY Count([Lab Occurrence Form].[1 0 Preanalytical (Before Testing)]) DESC;
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