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Home/ Questions/Q 7820609
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Editorial Team
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Editorial Team
Asked: June 2, 20262026-06-02T07:21:51+00:00 2026-06-02T07:21:51+00:00

here’s my code: var dict = new Dictionary<string, List<string>> { {AR, new List<string> {M4A1,

  • 0

here’s my code:

var dict = new Dictionary<string, List<string>>
                       {
                            {"AR", new List<string> {"M4A1", "M16A4", "SCAR-L", "CM901", "TYPE 95", "G36C","ACR 6", "MK14", "AK-47", "FAD"} },
                            {"SM", new List<string> {"MP5","UMP45","PP90M1","P90","PM-9","MP7"}},
                            {"LM", new List<string>{"L86 LSW","MG36", "PKP PECHENEG","MK46","M60E4"}},
                            {"SR", new List<string>{"BARRET .50 CAL","L118A","DRAGUNOV","AS50","RSASS","MSR"}},
                            {"SG", new List<string>{"USA512","KS612","SPAS-12","AA-12","STRIKER","MODEL 1887"}},
                            {"RS", new List<string>{"RIOT SHIELD"}}


                       };

I want to have a random item out of a random list in this dictionary output in a textBox. Thanks, any help is appreciated! Also, i’m developing for Windows Phone 7 if it makes it any different.

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  1. Editorial Team
    Editorial Team
    2026-06-02T07:21:52+00:00Added an answer on June 2, 2026 at 7:21 am

    From here: Random entry from dictionary

    There is a far more efficient method to randomise the dictionary once and make it available for selection:

    public IEnumerable<TValue> RandomValues<TKey, TValue>(IDictionary<TKey, TValue> dict)
    {
        Random rand = new Random();
        List<TValue> values = Enumerable.ToList(dict.Values);
        int size = dict.Count - 1;
        while(true)
        {
            yield return values[rand.Next(size)];
        }
    }
    

    And then:

    var rand = new Random();
    var randomDict = RandomValues(dict);
    var randList = randomDict.First();
    var randVal = randList[rand.Next(randList.Count - 1)];
    
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