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Home/ Questions/Q 904851
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Editorial Team
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Editorial Team
Asked: May 15, 20262026-05-15T16:07:08+00:00 2026-05-15T16:07:08+00:00

Heres my code: void *PrintLine(void *line) { printf(Line: #%s\n, (char *)line); pthread_exit(NULL); } int

  • 0

Heres my code:

void *PrintLine(void *line)
{
    printf("Line: #%s\n", (char *)line);
    pthread_exit(NULL);
}

int main (int argc, char *argv[])
{
    char line[80];
    while(fgets(line,sizeof(line),fp))
    {
        pthread_create(&threads[rt], NULL, PrintLine, (void*)line);
    }
    fclose(fp);
}

Please dont tell me that running a thread only to print a file line doesn’t make sense, I removed a lot of code so its easier to read and understand my problem.

As you would guess this code doesn’t work, what should I do to be able to print/use “line” inside the thread?

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-15T16:07:09+00:00Added an answer on May 15, 2026 at 4:07 pm

    You’re passing a pointer to line to the newly created thread, when your thread gets around to use line , perhapse fgets have written something else to it. Or perhaps it’s in the middle of writing something when your thread accesses it.

    You can pass a copy of the line you’ve read, remember to free() it when you’re done with it inside you thread.

    char *copy_of_line = strdup(line);
    if(copy_of_line)
      pthread_create(&threads[rt], NULL, PrintLine, copy_of_line);
    
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