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Editorial Team
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Asked: 2026-06-10T02:37:38+00:00

Here’s my code, what I’m trying to do is have javascript check a form

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Here’s my code, what I’m trying to do is have javascript check a form and then submit it to a PHP script via AJAX that will log the user in.

<!DOCTYPE html>
<html>
    <head>
        <title>RPEMS: Login</title>
        <link rel="stylesheet" type="text/css" href="../main.css"></link>
        <script src="//ajax.googleapis.com/ajax/libs/jquery/1.7.2/jquery.min.js" type="text/javascript"></script>
        <script type='text/javacript'>

$(function()
{
    $('.error').hide();
$('.button').click(function()
{
    $('.error').hide();
    var filter=/^([\w-]+(?:\.[\w-]+)*)@((?:[\w-]+\.)*\w[\w-]{0,66})\.([a-z]{2,6}(?:\.[a-z]{2})?)$/i;
    var email = $('input#email').val();
    var pass = $('input#pass').val();
    var err = false;

    if (!email)
    {
        $('label#emErr').show();
        $('input#email').focus();
        err = true;
    }

    if (!filter.test(email))
    {
        $('label#emValErr').show();
        $('input#email').focus();
        err = true;
    }

    if (!pass)
    {
        $('label#passErr').show();
        $('input#pass').focus();
        err = true;
    }

    if (err) return false;

    var dataString = 'email=' + email + '&pass=' + pass;
    $.ajax({
    type: "POST",
    url: "log.php",
    data: dataString,
    success: function(result)
    {
        if (result.success == true) window.location('../');
        else $('p#phpErr).html(result.message).show();
    }});
}
});

    </script>
</head>
<body>
    <div id="header">
        <img id="logo" src="../img/logo.png"></img>
            <ul id="navBar">
                <li class="navLink">
                    <a href="/">Home</a>
                </li>
                <li class="navLink">
                    <a href="/about">About/Contact Us</a>
                </li>
                <li class="navLink">
                    <a href="/calendar">Calendar</a>
                </li>
                <li class="navLink">
                    <a href="/login">Login</a>
                </li>
            </ul>
    </div>

    <form method='post' action=''>
        <fieldset>
            <label for='email'>Email: </label>
            <input name='email' id='email' type='text'></input>
            <br class='error'></br>
            <label for='email' class='error' id='emErr'>This field is required</label>
            <label for='email' class='error' id='emValErr'>Invalid email adress</label>
            <br class='error'></br>

            <label for='pass'>Password: </label>
            <input name='pass' id='pass' type='password'></input>
            <br></br>
            <label for='pass' class='error' id='passErr'>This field is required</label>
            <br class='error'></br>
            <p class='error' id='phpErr'></p>

            <input type='submit' name='submit' id='submit_btn' value='Submit'></input>
        </fieldset>
    </form>

Sadly when I load the page though, the errors aren’t hidden, any idea why?

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1 Answer

  1. Editorial Team

    You have a Uncaught SyntaxError: Unexpected token ) in your code. Please make sure you are always checking your console in the browser. See jsfiddle

    Here is your working jsfiddle. You are missing a single quote in your line else $('p#phpErr').html(result.message).show(); as well as a closing ); before your document.ready

    Please always check your console as this will help you out with errors like this… If you dont know how to use the console. Check this out

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