Question

Here’s my code:

x=0; 
for i=1:100
    x=x+sqrt(((1/((((2*i)-2)^2)*(((2*i)+2)^2)))*16)+8);
end

For some reason I keep getting the infinity value (inf) for x after this operation???

Can someone help explain why?

Answer 1

That is because you divide by zero at i==1 : Take a look at (2*i)-2 where i==1.

I can only guess that you actually meant to use i as the imaginary square root of -1. In that case, change the loop to:

x=0;
for k=1:100 x=x+sqrt(((1/((((2*i)-2)^2)*(((2*i)+2)^2)))*16)+8); end

And in that case the loop is not necessary at all.