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Home/ Questions/Q 5977855
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Editorial Team
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Editorial Team
Asked: May 22, 20262026-05-22T21:25:51+00:00 2026-05-22T21:25:51+00:00

Here’s my function call: removeTags(*buf, bufSize); which calls: void removeTags(char* dataBlock, unsigned long size)

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Here’s my function call:

removeTags(*buf, bufSize);

which calls:

void removeTags(char* dataBlock, unsigned long size) 
{
    char* start = dataBlock; 
    char* end = dataBlock + size;

    while(start < end)
    {
    //How do I replace the characters "\abc" with just nothing, ''.
        }

I want to replace any instances of the characters \abc with nothing.

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  1. Editorial Team
    Editorial Team
    2026-05-22T21:25:52+00:00Added an answer on May 22, 2026 at 9:25 pm

    Once you find an instance of \abc simply move all the characters after the \abc backwards four places (four because \abc is four chars long) (possibly using memmove).

    For instance:

    one two \abc three
            <----^ copy everything from the 't' down backwards over the \abc
    

    Note that after you do that, your end pointer will be invalidated so you’ll have to update it.

    Finding the position of a string within another string can be done with strstr for const char*s or std::string::find for std::strings. Of course, if you’re using std::string, then you could just use std::string::replace.

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