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Home/ Questions/Q 6074739
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Editorial Team
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Editorial Team
Asked: May 23, 20262026-05-23T10:24:58+00:00 2026-05-23T10:24:58+00:00

Here’s my problem, I have a variable wrongly encoded that I want to fix.

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Here’s my problem, I have a variable wrongly encoded that I want to fix. Long story short, I end up with:

myVar=u'\xc3\xa9'

which is wrong because it’s the character ‘é’ or \u00e9 UTF-8 encoded, not unicode.

None of the combinations of encode/decode I tried seem to solve the problem. I looked towards the bytearray object, but you must provide an encoding, and obviously none of them fits.

Basically I need to reinterpret the byte array into the correct encoding. Any ideas on how to do that?
Thanks.

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  1. Editorial Team
    Editorial Team
    2026-05-23T10:24:58+00:00Added an answer on May 23, 2026 at 10:24 am

    What you should have done.

    >>> b='\xc3\xa9'
    >>> b
    '\xc3\xa9'
    >>> b.decode("UTF-8")
    u'\xe9'
    

    Since you didn’t show the broken code that caused the problem, all we can do is make a complex problem more complex.

    This appears to be what you’re seeing.

    >>> c
    u'\xc3\xa9'
    >>> c.decode("UTF-8")
    Traceback (most recent call last):
      File "<stdin>", line 1, in <module>
      File "/Library/Frameworks/Python.framework/Versions/2.6/lib/python2.6/encodings/utf_8.py", line 16, in decode
        return codecs.utf_8_decode(input, errors, True)
    UnicodeEncodeError: 'ascii' codec can't encode characters in position 0-1: ordinal not in range(128)
    

    Here’s a workaround.

    >>> [ chr(ord(x)) for x in c ]
    ['\xc3', '\xa9']
    >>> ''.join(_)
    '\xc3\xa9'
    >>> _.decode("UTF-8")
    u'\xe9'
    

    Fix the code that produced the wrong stuff to begin with.

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