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Home/ Questions/Q 6330493
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Editorial Team
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Editorial Team
Asked: May 24, 20262026-05-24T17:52:51+00:00 2026-05-24T17:52:51+00:00

Here’s my problem: I have two .xsd files, let’s call them a.xsd and b.xsd.

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Here’s my problem:

I have two .xsd files, let’s call them a.xsd and b.xsd. What I want to achieve is to generate all the classes from a.xsd excluding the classes in b.xsd. Now the problem is, that a.xsd references a type in b.xsd (via a ), so even when excluded, the classes in b.xsd get build. Is there some way around this?

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  1. Editorial Team
    Editorial Team
    2026-05-24T17:52:52+00:00Added an answer on May 24, 2026 at 5:52 pm

    You can’t exclude a schema, but you can exclude a schema-derived package.

    Please see Ignoring packages:

    <jaxb:bindings schemaLocation="schema-ignored.xsd" node="/xsd:schema">
        <jaxb:schemaBindings>
            <jaxb:package name="org.jvnet.hyperjaxb3.ejb.tests.issuesignored"/>
        </jaxb:schemaBindings>
        <hj:ignored-package name="org.jvnet.hyperjaxb3.ejb.tests.issuesignored"/>
    </jaxb:bindings>
    

    Since you actually have a reference to a type from b.xsd somewhere in a.xsd you will need to break this reference. You can either ignore this property using hj:ignored or customize it with xjc:dom to make it a DOM element in the Java class.

    ps. I’m responding to users@hyperjaxb.java.net faster than to questions on SO.

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