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Home/ Questions/Q 8505993
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Editorial Team
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Editorial Team
Asked: June 11, 20262026-06-11T02:28:23+00:00 2026-06-11T02:28:23+00:00

Here’s my script: create table Country ( CountryId int primary key, Name varchar(255) );

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Here’s my script:

create table Country
(
CountryId int primary key,
Name varchar(255)
);

create table Person
(
PersonId int primary key,
Name varchar(255),
FOREIGN KEY (CountryId) references Country(CountryId)
);

I’m transitioning from MS SQL and trying to get a grasp on MySQL and starting off with my typical hello world of Person->Country relationship to get a feel for foreign keys.

I’m getting this error on PHPMyAdmin:

SQL query:

CREATE TABLE Person(

PersonId INT PRIMARY KEY , Name VARCHAR( 255 ) , FOREIGN KEY (
CountryId ) REFERENCES Country( CountryId ) );

MySQL said:

1072 – Key column ‘CountryId’ doesn’t exist in table

What newbie mistake am I making here?

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  1. Editorial Team
    Editorial Team
    2026-06-11T02:28:25+00:00Added an answer on June 11, 2026 at 2:28 am

    That’s because you had not created the column in Person that would be used in the foreign key, thus, Key column 'CountryId' doesn't exist in table. Here’s how you’d do it:

    CREATE TABLE Person(
        PersonId INT PRIMARY KEY , 
        Name VARCHAR( 255 ) , 
        CountryId int,
        FOREIGN KEY ( CountryId ) REFERENCES Country( CountryId )
    );
    
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