Sign Up

Sign Up to our social questions and Answers Engine to ask questions, answer people’s questions, and connect with other people.

Have an account? Sign In

Have an account? Sign In Now

Sign In

Login to our social questions & Answers Engine to ask questions answer people’s questions & connect with other people.

Sign Up Here

Forgot Password?

Don't have account, Sign Up Here

Forgot Password

Lost your password? Please enter your email address. You will receive a link and will create a new password via email.

Have an account? Sign In Now

You must login to ask a question.

Forgot Password?

Need An Account, Sign Up Here

Please briefly explain why you feel this question should be reported.

Please briefly explain why you feel this answer should be reported.

Please briefly explain why you feel this user should be reported.

Sign InSign Up

The Archive Base

The Archive Base Logo The Archive Base Logo

The Archive Base Navigation

  • Home
  • SEARCH
  • About Us
  • Blog
  • Contact Us
Search
Ask A Question

Mobile menu

Close
Ask a Question
  • Home
  • Add group
  • Groups page
  • Feed
  • User Profile
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Buy Points
  • Users
  • Help
  • Buy Theme
  • SEARCH
Home/ Questions/Q 566023
In Process

The Archive Base Latest Questions

Editorial Team
  • 0
Editorial Team
Asked: May 13, 20262026-05-13T12:56:03+00:00 2026-05-13T12:56:03+00:00

Here’s my simple ideal case scenario for when I’d like delayed job to run:

  • 0

Here’s my simple ideal case scenario for when I’d like delayed job to run:

  • When the first application server (whether through mongrel or passenger) starts, it’ll start my delayed job workers.
  • When the last running application server terminates, it’ll kill all the delayed job workers.

The first part (starting) is doable, although I’m not sure what the “right” or “best” way to do it is. Just make a conditional (on process not already running) system call to delayed_job start?

The second part (terminating) — well, I’m not sure if it is doable or not. Definitely have no idea how this effect could be accomplished.

Any thoughts or ideas?

Is there another way that you start/end delayed job workers that you think is best?

Side question:
The main questions above are for the production environment — a more difficult case because there are multiple app servers running at the same time. Could the same thing be easily done in the development environment (where there’s guaranteed to only be one application server, not a cluster of them) by forking a child process to run the delayed job workers that would always terminate when the parent terminates? How would I go about doing this?

  • 1 1 Answer
  • 0 Views
  • 0 Followers
  • 0
Share
  • Facebook
  • Report

Leave an answer
Cancel reply

You must login to add an answer.

Forgot Password?

Need An Account, Sign Up Here

1 Answer

  • Voted
  • Oldest
  • Recent
  • Random
  1. Editorial Team
    Editorial Team
    2026-05-13T12:56:03+00:00Added an answer on May 13, 2026 at 12:56 pm

    You could definitely pull the terminating off with god.

    Simply watch the app processes and god will fire a callback when they’re all stopped.

    • 0
    • Reply
    • Share
      Share
      • Share on Facebook
      • Share on Twitter
      • Share on LinkedIn
      • Share on WhatsApp
      • Report

Sidebar

Related Questions

Here's my scenario - I have an SSIS job that depends on another prior
Here's the situation. I developed a simple examination system with registration forms. I used
here is my configuration: http://domain.com (obviously fictitious name...) hosted on a server running Apache
Here is a simple timepicker to jQuery UI's datepicker <script type=text/javascript> /* <![CDATA[ */
Here I have an int x=3; NSLog(@%i, x); How to have it displayed like
Here is a simple demonstration of what I'm talking about js in head tag:
Here a simple question : What do you think of code which use try
Here's what I'm trying to do... It's quite simple and obviously there must be
Here is my question. I am having this simple menu. <div id=menu> <ul> <li>
Here's a coding problem for those that like this kind of thing. Let's see

Explore

  • Home
  • Add group
  • Groups page
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Users
  • Help
  • SEARCH

Footer

© 2021 The Archive Base. All Rights Reserved
With Love by The Archive Base

Insert/edit link

Enter the destination URL

Or link to existing content

    No search term specified. Showing recent items. Search or use up and down arrow keys to select an item.