Sign Up

Sign Up to our social questions and Answers Engine to ask questions, answer people’s questions, and connect with other people.

Have an account? Sign In

Have an account? Sign In Now

Sign In

Login to our social questions & Answers Engine to ask questions answer people’s questions & connect with other people.

Sign Up Here

Forgot Password?

Don't have account, Sign Up Here

Forgot Password

Lost your password? Please enter your email address. You will receive a link and will create a new password via email.

Have an account? Sign In Now

You must login to ask a question.

Forgot Password?

Need An Account, Sign Up Here

Please briefly explain why you feel this question should be reported.

Please briefly explain why you feel this answer should be reported.

Please briefly explain why you feel this user should be reported.

Sign InSign Up

The Archive Base

The Archive Base Logo The Archive Base Logo

The Archive Base Navigation

  • SEARCH
  • Home
  • About Us
  • Blog
  • Contact Us
Search
Ask A Question

Mobile menu

Close
Ask a Question
  • Home
  • Add group
  • Groups page
  • Feed
  • User Profile
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Buy Points
  • Users
  • Help
  • Buy Theme
  • SEARCH
Home/ Questions/Q 632987
In Process

The Archive Base Latest Questions

Editorial Team
  • 0
Editorial Team
Asked: May 13, 20262026-05-13T20:08:09+00:00 2026-05-13T20:08:09+00:00

Here’s the code: .386 ;target for maximum compatibility .model small,stdcall ;model .code main: int

  • 0

Here’s the code:

.386 ;target for maximum compatibility
.model small,stdcall ;model
.code
    main:
        int 20h
    END main

Result: http://img705.imageshack.us/img705/3738/resultom.png

“test.exe has stopped working” – always right when it reaches the interrupt.

This is the interrupt I’m trying to use. It should simply exit the program. Others I’ve tried include character input/output, etc.. Nothing works.

I’m on windows 7, using masm32 with the WinAsm IDE.

There are so many cool things it seems I should be able to do with interrupts… however, it crashes whenever I try to use an interrupt – always the same way.

This seems related and possibly useful: DOS Interrupt in masm x86 assembly crashing

…but I haven’t really been able to figure anything out from it.

Any suggestions?

  • 1 1 Answer
  • 0 Views
  • 0 Followers
  • 0
Share
  • Facebook
  • Report

Leave an answer
Cancel reply

You must login to add an answer.

Forgot Password?

Need An Account, Sign Up Here

1 Answer

  • Voted
  • Oldest
  • Recent
  • Random
  1. Editorial Team
    Editorial Team
    2026-05-13T20:08:10+00:00Added an answer on May 13, 2026 at 8:08 pm

    Yep. Interrupts of this nature are specifically for MS-DOS, and as such worked in Windows ME and previous but will not work on the NT architecture except under the DOS emulator (command.com). I have no idea if this still ships with Windows 7 – I know x64 versions of Windows don’t have it by default.

    If you’re writing Native NT Apps (you’re unlikely to be doing this if you don’t know what one is, but if you want to find out have a look at Mark Russinovich’s Blog at MSDN) here’s a list of NT interrupts and their corresponding functions: http://www.ctyme.com/intr/rb-4249.htm

    Other than that, you want to call a function in the Win32 API: http://msdn.microsoft.com/en-us/library/aa383749%28VS.85%29.aspx

    Edit: and in that code sample, you’ve not specified any options for the interrupt, done through the registers. Oh and you could get it working provided you assemble for DOS and not for Windows. If you use a Linker you’ll likely be creating a Windows PE executable. However, if you’re on 64-bit Windows, as I’ve said, don’t try.

    One thing you could do is install a virtual machine system such as VirtualBox or VMware and then install FreeDOS. It shouldn’t take up much RAM at all and will let you experiment with assembly/dos freely.

    • 0
    • Reply
    • Share
      Share
      • Share on Facebook
      • Share on Twitter
      • Share on LinkedIn
      • Share on WhatsApp
      • Report

Sidebar

Related Questions

Here is a code snippet I was working with: int *a; int p =
Here's my code in the <head></head> : <link rel=stylesheet href=http://code.jquery.com/mobile/1.1.0/jquery.mobile-1.1.0.min.css /> <script type=text/javascript src=http://code.jquery.com/jquery-1.7.1.min.js></script>
Here is the code in a function I'm trying to revise. This example works
Here is the code: create table `team`.`User`( `UserID` bigint NOT NULL AUTO_INCREMENT , `Username`
Here is my SQL script CREATE TABLE tracks( track_id int NOT NULL AUTO_INCREMENT, account_id
Here is an example: I write html code inside of textarea, then I swap
here is my php code $titikPetaInti = array(); while($row = mysql_fetch_assoc($hasil2)) { $titikPetaInti[] =
Here's a piece of code I copied from http://www.schillmania.com/content/projects/javascript-animation-1/demo/ Very simple JS animation: function
Here is the code I'm using inside my AsyncTask DefaultHttpClient httpClient = new DefaultHttpClient();
Here is my class: public class A{ private void doIt(int[] X, int[] Y){ //change

Explore

  • Home
  • Add group
  • Groups page
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Users
  • Help
  • SEARCH

Footer

© 2021 The Archive Base. All Rights Reserved
With Love by The Archive Base

Insert/edit link

Enter the destination URL

Or link to existing content

    No search term specified. Showing recent items. Search or use up and down arrow keys to select an item.