Question

Here’s the code I have which takes a string and reverse it

    name = "I CAN REVERSE THIS"

    def reverse_string(name_string)
      string_arr = []
      string_arr = name_string.split('')

      for i in 1..(string_arr.length)
        new_string = "#{new_string}#{string_arr[-i]}"
      end

      #return new_string
    end

    new_name = reverse_string(name)
    puts new_name

Why does my reverse_string function returns “1..18” if no return actions is called inside the function, but returns expected results if return action is called?

Answer 1

In Ruby, a method’s implicit return value (if no explicit call to return is being made) is the return value of the last statement in that method. In this case that is the for, which apparently returns what it iterated over.