Sign Up

Sign Up to our social questions and Answers Engine to ask questions, answer people’s questions, and connect with other people.

Have an account? Sign In

Have an account? Sign In Now

Sign In

Login to our social questions & Answers Engine to ask questions answer people’s questions & connect with other people.

Sign Up Here

Forgot Password?

Don't have account, Sign Up Here

Forgot Password

Lost your password? Please enter your email address. You will receive a link and will create a new password via email.

Have an account? Sign In Now

You must login to ask a question.

Forgot Password?

Need An Account, Sign Up Here

Please briefly explain why you feel this question should be reported.

Please briefly explain why you feel this answer should be reported.

Please briefly explain why you feel this user should be reported.

Sign InSign Up

The Archive Base

The Archive Base Logo The Archive Base Logo

The Archive Base Navigation

  • Home
  • SEARCH
  • About Us
  • Blog
  • Contact Us
Search
Ask A Question

Mobile menu

Close
Ask a Question
  • Home
  • Add group
  • Groups page
  • Feed
  • User Profile
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Buy Points
  • Users
  • Help
  • Buy Theme
  • SEARCH
Home/ Questions/Q 6572427
In Process

The Archive Base Latest Questions

Editorial Team
  • 0
Editorial Team
Asked: May 25, 20262026-05-25T15:00:17+00:00 2026-05-25T15:00:17+00:00

Here’s the code: public class Deck { private Card[] cards; public Deck() { cards

  • 0

Here’s the code:

public class Deck {

    private Card[] cards;

    public Deck() {
        cards = new Card[52];
        String[] ranks = {"ace","two","three","four","five","six","seven","eight","nine","ten","jack","queen","king"};
        String[] suits = {"hearts","diamonds","clubs","spades"};
        for(int i = 0; i < suits.length; i++) {
            for(int n = 0; n < ranks.length; n++) {
                cards[cards.length] = new Card(ranks[i],suits[n]);
            }
        }
    }
}

As you can see, this loops though the two given arrays and generates a card for every combination. There are 13 ranks x 4 suits = 52 cards. I expected that on the 52nd iteration, cards.length would be 51, but the compiler says

Exception in thread "main" java.lang.ArrayIndexOutOfBoundsException: 52
    at com.cards.Deck.<init>(Deck.java:14)

Why is that?

  • 1 1 Answer
  • 0 Views
  • 0 Followers
  • 0
Share
  • Facebook
  • Report

Leave an answer
Cancel reply

You must login to add an answer.

Forgot Password?

Need An Account, Sign Up Here

1 Answer

  • Voted
  • Oldest
  • Recent
  • Random
  1. Editorial Team
    Editorial Team
    2026-05-25T15:00:17+00:00Added an answer on May 25, 2026 at 3:00 pm

    The issue is that cards.length is not the total number of elements used in the array; it’s the total number of elements in the array, regardless of what you’ve stored in the array so far. Consequently, as soon as you execute the inner loop, this will try accessing the 52nd element of the array, causing the exception you’ve seen.

    To fix this, consider instead storing a counter that will keep track of the next free index, or use some simple math to derive the position that the card should go in from its suit and value. For example, since on each iteration of the outer loop you will write ranks.length elements to the array, on iteration (i, n) you will write to array index i * ranks.length + n. Using this, you could rewrite the inner loop as

        // Careful... still buggy!
        for(int i = 0; i < suits.length; i++) {
            for(int n = 0; n < ranks.length; n++) {
                cards[i * ranks.length + n] = new Card(ranks[i],suits[n]);
            }
        }
    

    Additionally, note that your access into the arrays is wrong. Right now, you’re writing

    new Card(ranks[i],suits[n]);
    

    However, i ranges over suits, not values. The proper code would be

    new Card(ranks[n],suits[i]);
    

    Which gives this final implementation:

        for(int i = 0; i < suits.length; i++) {
            for(int n = 0; n < ranks.length; n++) {
                cards[i * ranks.length + n] = new Card(ranks[n],suits[i]);
            }
        }
    

    More generally, though, don’t use the .length field of an array to track how many used elements there are. You’ll need to store that separately. Alternatively, consider using an ArrayList, which wraps an array and tracks this for you.

    Hope this helps!

    • 0
    • Reply
    • Share
      Share
      • Share on Facebook
      • Share on Twitter
      • Share on LinkedIn
      • Share on WhatsApp
      • Report

Sidebar

Related Questions

Here is my code, which takes two version identifiers in the form 1, 5,
Here is my code...I have two dimensional matrices A,B. I want to develop the
Here is my simplified data structure: Object1.h template <class T> class Object1 { private:
Here is my code: class Example { ...declarations/definitions... }; Example operator + (Example e)
Here's some code: class myclass { enum STAT { IDLE=0; READING, WRITING, PAINTING, SKATTING
Here is what I have: Dim cmsManager As New Telerik.Cms.CmsManager() Dim currentNode As Telerik.Cms.Web.CmsSiteMapNode
Here is the code I'm using http://jsbin.com/evike5/edit When the jQuery UI dialog is fired
Here's some of my production code (I had to force line breaks): task =
Here is a great article about GC may occur at unexpected point of code
Here is my javascript code for a cursor focus function to go to username

Explore

  • Home
  • Add group
  • Groups page
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Users
  • Help
  • SEARCH

Footer

© 2021 The Archive Base. All Rights Reserved
With Love by The Archive Base

Insert/edit link

Enter the destination URL

Or link to existing content

    No search term specified. Showing recent items. Search or use up and down arrow keys to select an item.