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Here’s the output dumped from od -cx(on linux you can reproduce with echo -ne "\r\n\n" |od -cx):
0000000 \r \n \n \0
0a0d 000a
0000003
The correct first 2 bytes should be 0d0a but it outputs 0a0d,why?
because you’re on a little-endian system? a 16-bit integer will be the high byte followed by the low byte; in this case the 2nd byte followed by the first.