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Home/ Questions/Q 7012581
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Editorial Team
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Editorial Team
Asked: May 27, 20262026-05-27T22:16:28+00:00 2026-05-27T22:16:28+00:00

Here’s the problem. When there is only one row in a subtotal grouping: the

  • 0

Here’s the problem. When there is only one row in a subtotal grouping:

  • the inserted row doesn’t come in at the right outlinelevel.
  • the subtotal doesn’t automatically include the inserted cell.

And here’s the code that inserts the row (i is defined earlier):

           For j = 2 To lEndRow * (1.5)
                If InStr(Cells(j, i), "Total") Then
                    Cells(j - 1, i).EntireRow.Insert
                    With Cells(j - 1, i)
                        .EntireRow.Font.ColorIndex = 3
                        .EntireRow.Interior.ColorIndex = 2
                    End With
                    Cells(j - 1, i).EntireRow.OutlineLevel = 2 ' This didn't work,
                         ' it puts all the inserted rows at 2 but doesn't group it
                         ' the subtotal.
                    Cells(j - 1, i + 8) = "1% Discount within terms"
                    Cells(j - 1, i + 24).FormulaR1C1 = "=Round((R[2]C[-8])*(.01),2)"
                    j = j + 1
                End If
            Next

I imagine this is an easy problem if you know it. I just don’t know it and it’s gotten me pretty frustrated. Happy first post to me and happy holidays to you.

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-27T22:16:29+00:00Added an answer on May 27, 2026 at 10:16 pm

    This is a guess but I think it is worth a try.

    From MS Help’s About outlining a worksheet

    • “Data to be outlined should be in range, where each column has a label in the first row and contains similar facts, and there are no blank rows or columns [my highlighting] within the range.”

    At the time you set the outline, the sub-total row is blank so cannot be part of the range. Try:

                 Cells(j - 1, i + 8) = "1% Discount within terms"
                 Cells(j - 1, i + 24).FormulaR1C1 = "=Round((R[2]C[-8])*(.01),2)"
                 Cells(j - 1, i).EntireRow.OutlineLevel = 2
    

    Best of luck.

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