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Home/ Questions/Q 4619162
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Editorial Team
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Editorial Team
Asked: May 22, 20262026-05-22T02:23:12+00:00 2026-05-22T02:23:12+00:00

Here’s the problems… I have 4 tables: users , groups , users_groups , and

  • 0

Here’s the problems…

I have 4 tables: users, groups, users_groups, and emails. Note that users_groups references both the groups and users table. In other words, each time a user joins a group, the userId and groupId is entered into the users_groups table. A user can join multiple groups.

CREATE TABLE app.users (
`id` INT NOT NULL AUTO_INCREMENT ,
`firstName` INT NOT NULL ,
`lastName` INT NOT NULL ,
PRIMARY KEY (`id`)
) ENGINE = InnoDB;

CREATE TABLE app.groups (
`id` INT NOT NULL AUTO_INCREMENT ,
`groupName` VARCHAR(32) NOT NULL ,
PRIMARY KEY (`id`)
) ENGINE = InnoDB;

CREATE TABLE app.users_groups (
`id` INT NOT NULL AUTO_INCREMENT ,
`userId` INT NOT NULL ,
`groupId` INT NOT NULL ,
PRIMARY KEY (`id`)
) ENGINE = InnoDB;

CREATE TABLE app.emails (
`id` INT NOT NULL AUTO_INCREMENT ,
`userId` INT NOT NULL ,
`email` VARCHAR(32) NOT NULL ,
PRIMARY KEY (`id`)
) ENGINE = InnoDB;

Now I would like to query these tables and display the result like this:

 +---------+-------------------+--------------+
 |name     |emails             |groups        |
 +---------+-------------------+--------------+
 |John Doe |johndoe@mail.com,  |group1,group2,|
 |         |johndoe2@mail.com  |group3        |
 +---------+-------------+---------+----------+
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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-22T02:23:13+00:00Added an answer on May 22, 2026 at 2:23 am

    You could use group_concat for that:

    select  concat(u.Firstname, ' ', u.Lastname) as name
    ,       group_concat(distinct e.email separator ',') as emails
    ,       group_concat(distinct g.groupName separator ',') as groups
    from    users u
    left join
            users_groups ug
    on      ug.userId = u.id
    left join
            groups g
    on      g.Id = ug.GroupId
    left join
            emails e
    on      e.UserId = u.Id
    group by
            u.Id
    ,       u.Firstname
    ,       u.Lastnmae
    
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