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Home/ Questions/Q 6140273
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Editorial Team
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Editorial Team
Asked: May 23, 20262026-05-23T18:05:49+00:00 2026-05-23T18:05:49+00:00

Here’s the XAML code: <Application x:Class=WpfApplication2.App xmlns=http://schemas.microsoft.com/winfx/2006/xaml/presentation xmlns:x=http://schemas.microsoft.com/winfx/2006/xaml Startup=Application_Startup /> Backing code: using System.Windows;

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Here’s the XAML code:

<Application x:Class="WpfApplication2.App"
             xmlns="http://schemas.microsoft.com/winfx/2006/xaml/presentation"
             xmlns:x="http://schemas.microsoft.com/winfx/2006/xaml"
             Startup="Application_Startup" />

Backing code:

using System.Windows;

namespace WpfApplication2
{
    public partial class App : Application
    {
        private void Application_Startup(object sender, StartupEventArgs e)
        {
            new Window().ShowDialog();
            new Window().ShowDialog();
        }
    }
}

Window shows only one time and then application exits. Why??

UPDATE: I know that windows should show up consequently. But after I close first window second does not show up at all

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-23T18:05:50+00:00Added an answer on May 23, 2026 at 6:05 pm

    Try this

        private void Application_Startup(object sender, StartupEventArgs e)
        {
            var w1 = new Window();
            var w2 = new Window();
    
            w1.ShowDialog();
            w2.ShowDialog();
        }
    

    Paste form comment:

    I think when you close first window,application checks whether there are other windows,and it doesn’t find any (so application is closing), because second window haven’t been created

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