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Home/ Questions/Q 3792664
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Editorial Team
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Editorial Team
Asked: May 19, 20262026-05-19T12:39:26+00:00 2026-05-19T12:39:26+00:00

Here’s what I am trying to do in the bootstrapper: protected override void ConfigureContainer()

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Here’s what I am trying to do in the bootstrapper:

    protected override void ConfigureContainer()
    {
            Assembly someAssembly = Assembly.LoadFile(@".\SomeServiceImplementationLib.dll");

            Type someServiceImplementationType = someAssembly .GetType(@"SomeServiceImplementation");

            Container.RegisterType<ISomeServiceType, someServiceImplementationType >(new ContainerControlledLifetimeManager());


        base.ConfigureContainer();
    }

This doesnt compile saying “Type or namespace name expected” for someServiceImplementationType. But its indeed a type isn’t it?

Basically I want to load a particular assembly only if certain conditions are met at startup and if its loaded I would like to register a service implementation from the loaded assembly with the unity container. Is there any way to do this at all?

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-19T12:39:27+00:00Added an answer on May 19, 2026 at 12:39 pm

    You are confusing compile-type generics and run-time typing.

    Generics are a compile-time thing, unless you do a little bit of reflection magic to new up a new generic instance with the type… but that isn’t necessary.

    The Unity container has other extensions for RegisterType that are easy to use.

    Instead, just call the non-generic form:

    Container.RegisterType(typeof(ISomeServiceType), someServiceImplementationType, new ContainerControlledLifetimeManager())
    
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