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Home/ Questions/Q 6953469
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Editorial Team
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Editorial Team
Asked: May 27, 20262026-05-27T14:29:00+00:00 2026-05-27T14:29:00+00:00

Here’s what i have: jQuery.fn.convertInputType = function(t){ var e = this; e.each(function(i){ var o

  • 0

Here’s what i have:

jQuery.fn.convertInputType = function(t){
  var e = this;
  e.each(function(i){
    var o = jQuery(this)
    ,   c = o.clone();
    c.attr('type',t);
    o.replaceWith(c);
  });
  return e;
}

I can’t figure out what to return back out to make it chain, like:

$('.example').convertInputType('password').css('background','blue');

I thought i could build an array like newReturnObj[i] = o.replaceWith(c) or newReturnObj[i] = c or newReturnObj[i] = jQuery(c), but none work.

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-27T14:29:01+00:00Added an answer on May 27, 2026 at 2:29 pm

    Here, this works:

    $.fn.convertInputType = function ( type ) {  
    
        // we use .map() because we're replacing the set of elements  
        return this.map( function ( i, elem ) {
            var clone = $( this ).clone().attr( 'type', type );        
            $( this ).replaceWith( clone );        
            return clone[0];
        });  
    
    };
    

    Live demo: http://jsfiddle.net/qTqQr/1/

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