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Home/ Questions/Q 6822703
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Editorial Team
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Editorial Team
Asked: May 26, 20262026-05-26T21:41:43+00:00 2026-05-26T21:41:43+00:00

Here’s what I’ve got: {-# LANGUAGE MultiParamTypeClasses , FlexibleInstances #-} class ListResultMult r a

  • 0

Here’s what I’ve got:

{-# LANGUAGE MultiParamTypeClasses
           , FlexibleInstances #-}

class ListResultMult r a where
  lstM :: a -> [a] -> r

listM :: ListResultMult r a => a -> r
listM a = lstM a []


instance ListResultMult r a => ListResultMult (a -> r) a where
  lstM a as x = lstM x $ a:as

instance ListResultMult [a] a where
  lstM a as = reverse $ a:as

Here’s how it works:

> listM 'a' 'b' 'c' :: String
"abc"
> putStrLn $ listM 'a' 'b' 'c'
abc
> listM (1::Int) (2::Int) :: [Int]
[1,2]

Here’s how it fails

> sum $ listM 1 2
No instance for (ListResultMult (a2 -> [a0]) a1) ...
> listM 1 :: [Int]
No instance for (ListResultMult [Int] a0) ...

Contrast with printf:

instance Show a => ListResultMult (IO ()) a where
  lstM a as = print . reverse $ a:as

> listM "foo" "bar" -- boo
No instance for (ListResult t0 [Char]) ...
> printf "%s %s" "foo" "bar"
foo bar
> listM "foo" "bar" :: IO () -- yay
["foo","bar"]

Type unsafety:

> :t listM 2 "foo"
Some weird type is actually inferred

So here’s what I want to do:

  • Type Safety. I thought when I defined ListResultMult r a => ListResultMult (a -> r) a and ListResultMult [a] a, it would only permit you to build up homogeneous lists, and notice a type error when you don’t. Why didn’t it?
  • Defaulting. I have no clue what weirdness is going on with listM 1 :: [Int]. What’s up?
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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-26T21:41:44+00:00Added an answer on May 26, 2026 at 9:41 pm

    Type functions seem like just the ticket for this problem. Here’s a sample file:

    {-# LANGUAGE TypeFamilies #-}
    
    class ListResultMult r where
        type Elem r
        lstM :: Elem r -> [Elem r] -> r
    
    listM a = lstM a []
    
    instance (ListResultMult r, Elem r ~ a) => ListResultMult (a -> r) where
        type Elem (a -> r) = a
        lstM a as x = lstM x (a:as)
    
    instance ListResultMult [a] where
        type Elem [a] = a
        lstM a as = reverse (a:as)
    

    Here are your examples in ghci:

    *Main> listM 'a' 'b' 'c' :: String
    "abc"
    *Main> putStrLn $ listM 'a' 'b' 'c'
    abc
    *Main> listM 1 2 :: [Int]
    [1,2]
    *Main> sum $ listM 1 2
    3
    *Main> listM 1 :: [Int]
    [1]
    *Main> :t listM 'a' True
    
    <interactive>:1:7:
        Couldn't match type `Bool' with `Char'
        In the first argument of `listM', namely 'a'
        In the expression: listM 'a' True
    *Main> :t listM 2 "foo"
    
    <interactive>:1:7:
        No instance for (Num [Char])
          arising from the literal `2'
        Possible fix: add an instance declaration for (Num [Char])
        In the first argument of `listM', namely `2'
        In the expression: listM 2 "foo"
    
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