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Home/ Questions/Q 8394331
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Editorial Team
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Editorial Team
Asked: June 9, 20262026-06-09T20:01:53+00:00 2026-06-09T20:01:53+00:00

Here’s what my code looks like: Random = function(name) { this.name = name; this.addSomething

  • 0

Here’s what my code looks like:

Random = function(name) {
    this.name = name;

    this.addSomething = function(a, b) {
        return a + b;
    }
}

Random.prototype.addStuff = function(a, b, c, d) {
    return this.addSomething(a, b) + this.addSomething(b, d);
}

I need this.addSomething to only be available in the function itself and its prototypes, however this isn’t working.

Could someone point me in the right direction and show me how to do this? Thanks.

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-09T20:01:56+00:00Added an answer on June 9, 2026 at 8:01 pm

    The only way to make “private” members/methods is something like this:

    Random = function(name) {
        this.name = name;
    
        function add_something(a, b) {
            return a + b;
        }
        this.addStuff = function(a, b, c, d) {
            return add_something(a, b) + add_something(b, d);
        }
    }
    

    Edit: as RobG mentioned in his answer, this article by Douglas Crockford will help you understanding how public, private and privileged members/methods work in Javascript. It’s an extremely reccomended reading.

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