Question

Hey all. I’m working on a project for school where I need to pass a few parameters by reference through multiple functions. I understand how I can pass by reference from where the variables are declared to another function, like this:

main() {   int x = 0;   int y = 0;   int z = 0;    foo_function(&x, &y, &z); }  int foo_function(int* x, int* y, int* z) {   *x = *y * *z;   return 0; } 

However, how would I pass x, y, and z from foo function to another function? Something like this gives me all kinds of compiler warnings.

int foo_function(int* x,  int* y, int* z) {   *x = *y * *z;   bar(&x, &y, &z);   return 0; }  int bar(int* x, int* y, int* z) {   //some stuff } 

Answer 1

Just use:

bar(x, y, z); 

X, Y, and Z are already pointers – just pass them directly.

Remember – a pointer is a location in memory. The location doesn’t change. When you dereference the pointer (using *x = …), you are setting the value at that location. But when you pass it into a function, you are just passing the location in memory. You can pass that same location into another function, and it works fine.