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Home/ Questions/Q 904987
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Editorial Team
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Editorial Team
Asked: May 15, 20262026-05-15T16:08:28+00:00 2026-05-15T16:08:28+00:00

Hey all, I’m working on some code I inherited, it looks like one thread

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Hey all, I’m working on some code I inherited, it looks like one thread is setting a boolean member variable while another thread is in a while loop checking it. Will this actually work OK or should I change it to use synchronized getters or setters on the boolean var?

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  1. Editorial Team
    Editorial Team
    2026-05-15T16:08:28+00:00Added an answer on May 15, 2026 at 4:08 pm

    In the case of reading and writing a primitive like bool or int declaring them as volatile will be plenty. When one threads read the other thread would have finished writing. The variable will never be in an invalid state.

    It’s probably fair to say that on the whole, the volatile keyword in
    Java is poorly documented, poorly understood, and rarely used. To make
    matters worse, its formal definition actually changed as of Java 5.
    Essentially, volatile is used to indicate that a variable’s value will
    be modified by different threads.

    Declaring a volatile Java variable means:

    1. The value of this variable will
      never be cached thread-locally: all
      reads and writes will go straight to
      “main memory”;
    2. Access to the variable acts as
      though it is enclosed in a
      synchronized block, synchronized on
      itself.

    We say “acts as though” in the second point, because to the programmer
    at least (and probably in most JVM implementations) there is no actual
    lock object involved.

    http://www.javamex.com/tutorials/synchronization_volatile.shtml

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