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Home/ Questions/Q 3784694
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Editorial Team
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Editorial Team
Asked: May 19, 20262026-05-19T11:24:56+00:00 2026-05-19T11:24:56+00:00

Hey everybody I’m working on a data scraping project and I’m looking for a

  • 0

Hey everybody I’m working on a data scraping project and I’m looking for a clean way to repeat a function call if an exception is raised.

Pseudo-code:

try:
    myfunc(x)
except myError:
    ###try to call myfunc(x) again Y number of times, 
        until success(no exceptions raised) otherwise raise myError2

I realize this isn’t best practice at all but I’m working through a number of different code/network layers that aren’t reliable and I can’t realistically debug them.

Right now I’m accomplishing this with a huge set of try\except blocks and it’s making my eyes bleed.

Elegant ideas anyone?

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-19T11:24:57+00:00Added an answer on May 19, 2026 at 11:24 am

    To do precisely what you want, you could do something like the following:

    import functools
    def try_x_times(x, exceptions_to_catch, exception_to_raise, fn):
        @functools.wraps(fn) #keeps name and docstring of old function
        def new_fn(*args, **kwargs):
            for i in xrange(x):
                try:
                    return fn(*args, **kwargs)
                except exceptions_to_catch:
                     pass
            raise exception_to_raise
        return new_fn
    

    Then you just wrap the old function in this new function:

    #instead of
    #risky_method(1,2,'x')
    not_so_risky_method = try_x_times(3, (MyError,), myError2, risky_method)
    not_so_risky_method(1,2,'x')
    
    #or just
    try_x_times(3, (MyError,), myError2, risky_method)(1,2,'x')
    
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