Question

Hey guys i have 2 scripts with me for file upload.

One is amazon s3 upload script. Using this script i can upload from computer. Another one is normal remote upload script.

I would like to implement remote upload feature in amazon s3.

This is the code what i have in “direct upload script”.

Html code

h1>Upload a file</h1>
<p>Please select a file by clicking the 'Browse' button and press 'Upload' to start uploading your file.</p>
    <form action="" method="post" enctype="multipart/form-data" name="form1" id="form1">
      <input name="theFile" type="file" />
      <input name="Submit" type="submit" value="Upload">
    </form>

PHP code to retreive post variables

$fileName = $_FILES['theFile']['name'];
$fileTempName = $_FILES['theFile']['tmp_name'];

My remote upload script code is as follows.

<form method="POST" action="<?=$self?>">
<input type="text" name="file[]"  size="45" value="">
<input name="submit" type="submit" id="submit" value="submit"></p>
</form>

php code to receive files

$files = $_POST['file'];

This is my question. How to convert my remote upload code

$files = $_POST[‘file’];

into

$fileName = $_FILES[‘theFile’][‘name’];
$fileTempName = $_FILES[‘theFile’][‘tmp_name’];

Hope you guys get my point. Thanks

Answer 1

You must set the enctype parameter on the <form> tag:

<form enctype="multipart/form-data" action="__URL__" method="POST">

Some more help is in the PHP manual: http://www.php.net/manual/en/features.file-upload.post-method.php

See specifically the second example.