Hey guys, im working through the Introduction to Programming in Java book and one of the exercises is this:
Empirical shuffle check. Run
computational experiments to check
that our shuffling code works as
advertised. Write a program
ShuffleTest that takes command-line
arguments M and N, does N shuffles of
an array of size M that is initialized
with a[i] = i before each shuffle, and
prints an M-by-M table such that row i
gives the number of times i wound up
in position j for all j. All entries
in the array should be close to N/M.
Now, this code just outputs a block of zeros…
public class ShuffleTest2 {
public static void main(String[] args) {
int M = Integer.parseInt(args[0]);
int N = Integer.parseInt(args[1]);
int [] deck = new int [M];
for (int i = 0; i < M; ++i)
deck [i] = i;
int [][] a = new int [M][M];
for (int i = 0; i < M; i++) {
for (int j = 0; j < M; j++) {
a[i][j] = 0 ;
for(int n = 0; n < N; n++) {
int r = i + (int)(Math.random() * (M-i));
int t = deck[r];
deck[r] = deck[i];
deck[i] = t;
for (int b = 0; b < N; b++)
{
for (int c = 0; c < M; c++)
System.out.print(" " + a[b][c]);
System.out.println();
}
}
}
}
}
}
What am i doing wrong? 🙁
Thanks
So a is like a history? As you are now it is always filled with zeroes just like you initialized, you never assign to it! After the “shuffling” for loop you need to set
Meaning that after i-th shuffle, card CARD_VALUE is in position POSITION. I don’t want to give you all the specifics, but it will take another for loop, and the nested for-loop for printing needs to be independent of any other loop, occuring when everything else is done.
Looks like you have a few things concerning the for-loops that you need to look over carefully. Trace the program flow manually or with a debugger and you’ll notice that some of those braces and code blocks need to be moved.
–TRY THIS–