Question

Hey I have an array with numbers in it.

Now I want to divide the value at 17th position of the array by the value at the first position of the array, then the 18th by the second, and so on. The results should build a new array.

Then I want to scan all values of the new array and if two or more successive values are bigger than 1.2, I want to add the result of dividing the first by the last value of that row for all of successive values. If one value is 1.2 and the next for example 0.8, the values of the array should not be changed.

Here is my code:

a = [1,2,3,4,5,9,5,13,14,17,19,23,19,34,46,12,13,45,46,67,78,79]

b = Array.new
c = Array.new

a.each_cons(18) { |c| b.push(c[17]/c[0] }

Do you have an idea how to implement the condition?

Answer 1

I think this will do it, although I selectively interpreted some things from your question. Specifically, in “of that row for all of successive values,” does “row” refer to the sliding block from each_cons? Ditto for “all of successive values.”

catch (:done) do
  for i in 2..b.length do
    b.each_cons(i) do |d| 
      for j in 2..d.length do 
        d.each_cons(j) do |g|
          if g.all? { |g| g > 1.2 }
            c = b.map { |f| f + (d[0].to_f/d[i-1].to_f) }
            break
          end
          if !c.empty? then throw :done end
        end
      end
    end
  end
end

puts c