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Editorial Team
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Editorial Team
Asked: May 13, 20262026-05-13T10:02:47+00:00 2026-05-13T10:02:47+00:00

Hey I’m just revising for my functional programming exam coming up on friday and

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Hey I’m just revising for my functional programming exam coming up on friday and I’m just working through exercises given by our lecturer. I’ve come across one which I neep a bit of help on:

6. a) Write a function that zips a given list xs with every list in a list yss of lists. Use partial
applications and lambda expressions to the greatest extent possible in defining your function.
b) Write a function that zips every list in a list yss of lists with a given list xs. Use partial
applications and lambda expressions to the greatest extent possible in defining your function.
The difference between your solutions to part a) and part b) of this problem illustrates that partially
applied functions must take their arguments in the correct order.

What I have at the moment for (a) is :

zipAll = (\xs (ys:yss) -> [(zip xs ys)] ++ zipAll xs yss)

It’s non-exaustive I know but could anyone give me some pointers?

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  1. Editorial Team
    Editorial Team
    2026-05-13T10:02:47+00:00Added an answer on May 13, 2026 at 10:02 am

    Its fine, I worked it out:

    zipList :: [a] -> [[b]] -> [[(a,b)]]
    zipList = \xs yss -> c xs yss
                            where
                                    c xs [] = []
                                    c xs (ys:yss) = zip xs ys :zipList xs yss
    

    Just wish I hadn’t posted this now 😛

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