Question

Heya guys, I have this small script and i need to grep all the files and leave only the ones that contain a keyword and I’m stuck on this, any help in pointing out my dumb errors is appreciated 🙂

#!/bin/bash

server=(server1...server24)

.
.
.

for ((n=0; n <= 24 ; n++))
do
        if grep -q "KEYWORD" directory/${server[$n]}.html ; then
                echo Empty
        else
                rm -f directory/${server[$n]}.html
        fi
done

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.
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Answer 1

You don’t have to make sure your count matches if you let your code do it for you in one of the following ways:

servers=(foo bar baz)
for server in ${servers[@]}
do
    if ! grep -qs "KEYWORD" directory/$server.html 
    then
        rm ...

or

servers=(foo bar baz)
for ((n = 0; n < ${#servers[@]}; n++))
do
    if ! grep -qs "KEYWORD" directory/${servers[$n]}.html 
    then
        rm ...

Use ! to invert the condition so that it’s “if the file does NOT contain the keyword, then delete it”.

Use the grep option -q to quiet the output and -s to suppress error messages.