Question

Heythere.
I need your guys help with file renaming using a .bat file.
I got multiple files that I need to be cropped after specified character number.
For exmample, I want to crop name of the files after their fifth character, this way

filename.exe > filen.exe
anothername.exe > anoth.exe
absolutelydifferentname.exe > absol.exe

And, if possible, I’d like to know how to do the opposite. I mean, leaving the certain # of characters at the end, cropping from the beginning of the filename.

Thank you.

Answer 1

If you want to do it in a batch file, the following should work:

@echo off

setlocal ENABLEDELAYEDEXPANSION

for %%i in (<Directory name here>\*) do (
  set filename=%%~ni
  ren "%%~i" "!filename:~0,5!%%~xi"
)

endlocal

If you wish to change the number of characters used to construct the final filenames, change the “5” in ren "%%~i" "!filename:~0,5!%%~xi".

To take the last 5 characters try: ren "%%~i" "!filename:~-5!%%~xi"

For all except the first 5 characters: ren "%%~i" "!filename:~5!%%~xi"