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Home/ Questions/Q 783997
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Editorial Team
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Editorial Team
Asked: May 14, 20262026-05-14T20:38:28+00:00 2026-05-14T20:38:28+00:00

Hi all I have the following in a member function int tt = 6;

  • 0

Hi all I have the following in a member function

int tt = 6; 
vector<set<int>>& temp = m_egressCandidatesByDestAndOtMode[tt]; 
set<int>& egressCandidateStops = temp.at(dest);

and the following declaration of a member variable

map<int, vector<set<int>>> m_egressCandidatesByDestAndOtMode;

However I get an error when compiling (Intel Compiler 11.0)

1>C:\projects\svn\bdk\Source\ZenithAssignment\src\Iteration\PtBranchAndBoundIterationOriginRunner.cpp(85): error: no operator "[]" matches these operands
1>            operand types are: const std::map<int, std::vector<std::set<int, std::less<int>, std::allocator<int>>, std::allocator<std::set<int, std::less<int>, std::allocator<int>>>>, std::less<int>, std::allocator<std::pair<const int, std::vector<std::set<int, std::less<int>, std::allocator<int>>, std::allocator<std::set<int, std::less<int>, std::allocator<int>>>>>>> [ const int ]
1>          vector<set<int>>& temp = m_egressCandidatesByDestAndOtMode[tt]; 
1>                                                                    ^

I know it’s got to be something silly but I can’t see what I’ve done wrong.

UPDATE I’m calling this from a const member function which is why the member variable’s type is const so I thought that something like the following should fix it:

int dest = 0, tt = 6; 
const set<int>& egressCandidateStops = m_egressCandidatesByDestAndOtMode[tt].at(dest); 

But no dice… still the same error.

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-14T20:38:28+00:00Added an answer on May 14, 2026 at 8:38 pm

    operand types are: const std::map< int …

    map::operator[] does not work with a const map.

    I answered this a few days ago.

    map::operator[] is a little odd. It
    does this:

    1. Look for the key.
    2. If found, return it.
    3. If not, insert it and default-construct its associated
      value.
    4. Then return a reference to the new value.

    Step 3 is incompatible with constness.
    Rather than have two
    differently-functioning operator[]
    overloads, the language forces you to
    use map::find for const objects.

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