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Home/ Questions/Q 7722989
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Editorial Team
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Editorial Team
Asked: June 1, 20262026-06-01T04:19:52+00:00 2026-06-01T04:19:52+00:00

Hi can some one point me some guidance, i pretend to pass the value

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Hi can some one point me some guidance, i pretend to pass the value of function schema to a variable that will be used as the argument step inside the range module.
i hope its clear .. sorry the newbie guys.
after some trials i got the edit fine.

import os
import sys


def schema(x):
    if x == 'M':
        step=1
    else:
        step=2
        return step

def main():
    left_start = 1
    left_end = 9
    sch = schema('M')

    range1= range(left_start,left_end,sch)
    if 2 in range1:
        print "In range"
    else:
        print "Missing in range"

if __name__ == '__main__':
    main()
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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-01T04:19:53+00:00Added an answer on June 1, 2026 at 4:19 am

    Your code has a problem with indentation. The following:

    def schema(x):
        if x == 'M':
            step=1
        else:
            step=2
            return step
    

    should read

    def schema(x):
        if x == 'M':
            step=1
        else:
            step=2
        return step
    

    Otherwise, the function returns None when x == 'M'.

    A more concise way to write that function is:

    def schema(x):
        return 1 if x == 'M' else 2
    
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