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Home/ Questions/Q 7718387
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Editorial Team
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Editorial Team
Asked: June 1, 20262026-06-01T03:09:21+00:00 2026-06-01T03:09:21+00:00

Hi guys i have an array that is populated with dates Array ( [0]

  • 0

Hi guys i have an array that is populated with dates

Array
(
    [0] => 2012-04-04
    [1] => 2012-04-06
    [2] => 2012-04-06
    [3] => 2012-04-06
    [4] => 2012-04-06
    [5] => 2012-04-06
    [6] => 2012-04-06
    [7] => 2012-04-11
    [8] => 2012-04-12
    [9] => 2012-04-12
    [10] => 2012-04-13
    [11] => 2012-04-13
    [12] => 2012-04-13
    [13] => 2012-04-13
    [14] => 2012-04-13
    [15] => 2012-04-13
    [16] => 2012-04-13
)

How would I loop through the array and find the difference in days between items next to each other in array. For example i would want to echo out

difference between [0] and [1] is “2” days
difference between [1] and [2] is “0” days

🙂

Managed to get some output from the top answer however i only want it to display if there is a difference in date.

No output from this if statement though – UPDATED –

$count = count($datestack);



for ($i = 0; $i < $count - 1; $i++) {
    $datetime1 = new DateTime($datestack[$i]);
    $datetime2 = new DateTime($datestack[$i + 1]);
    $interval = $datetime1->diff($datetime2);
    if ($arr[$i] === $arr[$i+1]){
     echo $interval->format('%R%a days');
    }

} 
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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-01T03:09:22+00:00Added an answer on June 1, 2026 at 3:09 am

    What you need is DateTime::diff.

    Example:

    $datetime1 = new DateTime('2012-04-04');
    $datetime2 = new DateTime('2012-04-06');
    $interval = $datetime1->diff($datetime2);
    echo $interval->format('%R%a days');
    

    And you just need loop your array to do what you want.

    $count = count($arr);
    for ($i = 0; $i < $count - 1; $i++) {
        $datetime1 = new DateTime($arr[$i]);
        $datetime2 = new DateTime($arr[$i + 1]);
        $interval = $datetime1->diff($datetime2);
        echo $interval->format('%R%a days');
    } 
    
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