Question

Hi having a bit of a problem what I’m trying to do is once a user has clicked a button
the button should show a popup of a form so they might enter a value which is a date so it may be used for future uses and the popup has a submit button so process the action
with this code:

     if (isset($_POST['unenroll'])){
        $sql1="Update tbl_enroll SET status='unEnrolled' , counter='0' 
              period='$pweek";
                    $pow = mysql_query($sql1) or die (mysql_error());
                    } 

I am having a problem on how to create the popup so far i have this:

     onclick="window.open‘unenroll.php’,‘Unenroll’,
   ‘menubar=no,width=200,height=100,toolbar=no’)"

So far it just not creating the popup form. would appreciate any help.

Answer 1

You use the wrong quotes and also a bracket is missing. Try this here:

onclick="window.open('unenroll.php', 'Unenroll', 'menubar=no,width=200,height=100,toolbar=no')"

Note that this must be in one line and also care about the php variable $pweek If that comes from the client you open a blind sql injection hole.

In your SQL statement is also a quote and a comma missing:

$sql1="Update tbl_enroll SET status='unEnrolled', counter='0', period='$pweek'";