Question

Hi i am having results and its contains a checkbox as <input type='checkbox' name="ChkS[]" value='<? echo $rs->id?>'>

I have a print out list option in the footer as <input type="button" value="Show Printable List" class="butten" onClick="openPrint()">

Its opening the printable list in new pop up window.

function openPrint() {
    window.open("<?= $_SERVER["PHP_SELF"]; ?>?<?=$qstring?>&print=true","","width=1024,height=600,menubar=yes,resizable=yes, scrollbars=yes");
}

I am in need to use the above select checkbox and it should show the selected print list in the pop up ?

I hope it should not be problem any1 to understand it. Any help ?

Answer 1

Javascript Modification:

var s = "";
function changeval(value) {
    s = value;
}
function openPrint() {
    alert(s);
    window.open("<?= $_SERVER["PHP_SELF"]; ?>?<?=$qstring?>&print=true","","width=1024,height=600,menubar=yes,resizable=yes, scrollbars=yes");
}

HTML Modification:

<input type='checkbox' name="ChkS[]" value='<? echo $rs->id?>' onchange="changeval(this.value)" />

What I have done?

1. Created an Global Variable s.

2. Attached or Bind onchange event on checkbox and set the value of Variable s according.

3. Now, You have variable s with value, you just have to use it in any function.