Question

Hi I am trying to show 1.php on div firstresult and 1b.php to div secondresult. My code is not correct though. I want one option value to trigger two div and two php files. like to get the val and display 1.php to first and 1b.php to the second.

<script language='JavaScript'>
$(document).ready(function() {
$('#termid').change(function() {
    var val = $(this).val();
    $('#firstresult').load(val + '.php', { value: val }).$('#secondresult').load(val + 'b.php', { value: val });
});
});
</script>

    <form>
        <select id="termid">
            <option value="">- select -</option>
            <option value="1">Option 1</option>
            <option value="2">Option 2</option>
        </select>  
    </form>

<div id="firstresult"></div>
<div id="secondresult"></div>

Answer 1

You almost have it right – you just need to separate the two statements:

$('#firstresult').load(val + '.php', { value: val });
$('#secondresult').load(val + 'b.php', { value: val });