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Home/ Questions/Q 4622070
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Editorial Team
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Editorial Team
Asked: May 22, 20262026-05-22T02:47:30+00:00 2026-05-22T02:47:30+00:00

Hi I have a function A ( xy * abc) that takes a pointer

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Hi
I have a function A ( xy * abc) that takes a pointer to a structure.

typedef struct
{
int a;
char * b;
} xy;

typedef struct
{
xy c;
xy d;
} uv;

uv *sha;

If i need to call the function A for c and d using uv how should I pass the argument? I am calling function A by using this:

A (&sha->c);
A (&sha->d);

Is this call correct?

Kindly help me

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  1. Editorial Team
    Editorial Team
    2026-05-22T02:47:31+00:00Added an answer on May 22, 2026 at 2:47 am

    If uv is a struct, and not a pointer to struct, you need to do A(&uv.c), but in your case, uv is a struct type, not an actual struct, you need to have a variable of type uv:

    uv somevar;
    A(&somevar.c);
    
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