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Home/ Questions/Q 942819
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Editorial Team
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Editorial Team
Asked: May 15, 20262026-05-15T22:20:08+00:00 2026-05-15T22:20:08+00:00

Hi I have a json string converted unsing the JSON framework into a dictionary

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Hi I have a json string converted unsing the JSON framework into a dictionary and I need to extract its content. How could I iterate to the nested dictionaries? I have already this code that allows me to see the dictionary:

NSDictionary *results = [responseString JSONValue]; 
NSMutableArray *catArray = [NSMutableArray array];

for (id key in results) {
    NSLog(@"key: %@, value: %@", key, [results objectForKey:key]);
    [catArray addObject:key];
    NSString *cat = key;
}

Could someone provide a sample on how to get to all the levels of the dic not using the name of the keys?

The result structure of the dic is like this: http://www.freeimagehosting.net/uploads/e7c020d697.png

alt text http://www.freeimagehosting.net/uploads/e7c020d697.png

thanks

ldj

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  1. Editorial Team
    Editorial Team
    2026-05-15T22:20:08+00:00Added an answer on May 15, 2026 at 10:20 pm

    Try

    
    
    for ((id) key in [results allKeys]) {
        NSLog(@"key: %@, value: %@", key, [results objectForKey:key]);
        [catArray addObject:key];
        NSString *cat = key;
    }
    
    

    Hope that helped.

    EDIT:
    i’m not sure if i understand your structure correct, but i’m asuming you have some values in your dictionairy which are again dictionairies.
    if you want to interate through a dictionairy which is located inside another one you could do it like this:

    
    for ((id) key in [results allKeys]) {
        id value = [results objectForKey:key];
        if ([value isKindOfClass:[NSDictionary class]]) {
            NSDictionary* newDict = (NSDictionary*)value;
            for ((id) subKey in [newDict allKeys]) {
                ...
            }
        }
    }
    

    Of couse if you know the specific key to your desired dictionairy, you can check for that instead of checking if the value is a dict. But maybe it’s not a bad idea to check that in both cases…

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